## Question

Figure shows the displacement-time graphs of two simple harmonic motions I and II. From the graphs it follows that the two motion I and II have

### Solution

Equal amplitudes, equal frequencies and finite phase difference

It is clear from the figure that motions I and II have the same amplitude (maximum displacement) = 1 cm and the same time period = 4 s. But at time *t* = 0, the displacement of I is zero whereas that of II is negative maximum (–1cm). Hence they have a finite phase difference.

#### SIMILAR QUESTIONS

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